Respuesta :

[tex]\text{y}=6 \ \text{and} \ \text{z}=2\\\\\dfrac{3\text{y}-\text{z}}{\text{y}+5\text{z}}=\dfrac{3\cdot6-2}{6+5\cdot2}=\dfrac{18-2}{6+10}=\dfrac{16}{16}=\huge\boxed1[/tex]

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