We have that the see-saw will be balance if a weight of [tex]x=15kg[/tex] is added to Nural's side of the see-saw
[tex]x=15kg[/tex]
From the Question we are told that
Wan’s mass is [tex]M_w=45 kg[/tex]
Nurul’s mass is [tex]M_n= 30 kg.[/tex]
Generally
The Will be balance when the weight on both sides of the see-saw are equal
[tex]M_w=M_n+x[/tex]
[tex]45=30+x[/tex]
[tex]x=45-30[/tex]
[tex]x=15kg[/tex]
In conclusion
The see-saw will be balance if a weight of [tex]x=15kg[/tex] is added to Nural's side of the see-saw
[tex]x=15kg[/tex]
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