Answer:
Putting x= 2
[tex]( - 5) \times 2 = - 10 \\ - 10 = - 10[/tex]
putting x = -2
[tex]( - 5) \times ( - 2) = - 10 \\ 5 \times 2 = - 10 \\ 10 = - 10 \\ this \: is \: not \: correct \: equation[/tex]
putting x = 50
[tex]( - 5) \times 50 = - 10 \\ - 250 = - 10 \\ this \: is \: also \: not \: correct \: equation[/tex]
so, x = 2 is applicable.