Respuesta :

Answer:

Putting x= 2

[tex]( - 5) \times 2 = - 10 \\ - 10 = - 10[/tex]

putting x = -2

[tex]( - 5) \times ( - 2) = - 10 \\ 5 \times 2 = - 10 \\ 10 = - 10 \\ this \: is \: not \: correct \: equation[/tex]

putting x = 50

[tex]( - 5) \times 50 = - 10 \\ - 250 = - 10 \\ this \: is \: also \: not \: correct \: equation[/tex]

so, x = 2 is applicable.

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