seemeha seemeha

27-08-2021
Physics

contestada

xy+4z=

X=2
Y=2
Z=3

Solve for

Respuesta :

clockhart011 clockhart011

27-08-2021

Answer:

x×y=2×2=4. 4×z=4×3=12. 4+12=16

Answer Link

ambitious3161 ambitious3161

27-08-2021

X = 12
Y = 2
Z = 3
Put in xy+4z
12 x 2 + 4 x 3
=> 24 + 12
=> 36 Ans

Answer Link

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