Question

equilibrium between two isomers a and b (a and b have the same mol. wt) is attained when there is 5% by weight A and by difference, 95% by weight of B. What is the equilibrium constant

Answer 1

The equili constant assuming reaction is from isomer A to isomer B; 19

i.e. A ⇄ B = 19

Given data :

% wt of A = 5

% wt of B = 95

assume the mass of mixture = 100 g

wt of A = 5% of 100 = 5 g

wt of B = 95% of 100 = 95 g

∴ mole of A = 5/M mol,  mole of B = 95/M  mol   ( where M = molar mass )

expressing the equilibrium constant

A ⇄ B  

equilibrium constant = $\frac{[B]}{[A]}$ = $\frac{ (95/M) /V}{(5/M)/V}$  where V = volume

∴ Equilibrium constant = 19 assuming process is from A to B

hence the equilibrium constant = 19 assuming reaction process is from A to B

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