The equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4) is y = [tex]-\frac{5}{x} x-1[/tex]
Parallel lines have the same slope. Therefore, using slope intercept form.
y = mx + b
m = slope
b = y-intercept
Therefore,
5x + 2y = 12
2y = -5x + 12
[tex]y = -\frac{5}{2} x+12[/tex]
The slope of the line is [tex]-\frac{5}{2}[/tex]
Base on parallelism, for the line that passes through (-2, 4)
y = mx + b
4 = [tex]-\frac{5}{2} (-2)+b[/tex]
b = -1
Therefore,
y =
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