Respuesta :

Using pythagorean trplet

[tex]\\ \sf\longmapsto AC^2=AB^2+BC^2[/tex]

[tex]\\ \sf\longmapsto AC^2=6^2+8^2[/tex]

[tex]\\ \sf\longmapsto AC^2=36+64[/tex]

[tex]\\ \sf\longmapsto AC^2=100[/tex]

[tex]\\ \sf\longmapsto AC=\sqrt{100}[/tex]

[tex]\\ \sf\longmapsto AC=10[/tex]

Use the Pythagorean theorem:
a^2+b^2=c^2
Let the unknown hypotenuse be x:
6^2+8^2=x^2
36+64=x^2
100=x^2
x=10
The answer is the first choice: 10
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