Question

write an equation that contains points (0, 4) and is perpendicular to x-3y=-12

Answer 1

X-3(4)=-2
x-12=-2
So ya add the -12 to both side and you get X=10

Answer 2

Answer:

y= -3x+4

Step-by-step explanation:

x+12=3y

(x+12)/3 = y

slope =

$\frac{1}{3}$

the new slope = -3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

With the new slope, use the slope intercept form and the point to calculate the intercept: y = mx + b

4 = -3×(0) + b

b= 4

so y= -3x+4