Question

HELP PLEASE NOT MUCH TIME.
The equation y+6=1/3(x-9) is written in point-slope form. What is the equation written in slope-intercept form?

y = 1/8 x-3
y= 1/3x+9
y=1/3x-9
y=1/3x+3

Answer 1

The steps are to first distribute the 1/3 into (x-9) and then to move the +6 on the left over to the right:

First distribute:
y + 6 = 1/3(x-9) becomes y + 6 = 1/3x-3

Now subtract 6 from both sides:
y = 1/3 x - 3 - 6

y = 1/3 x - 9