Question

Reynaldo drew square EFGH. Then, he drew the image of it, square E'F'G'H', 4 centimeters to the left of the original figure. Line segment EF is 6 centimeters. How long is segment E'F'?

Answer 1

Answer:

6 centimeters

Step-by-step explanation:

Square E'F'G'H' is just square EFGH translated to the left.

It is still the same size, just in a different location.

Line segment EF is the same length as segment E'F'.

6 centimeters

Answer 2

The segment $E'F'$ is 6 centimeters long.

According to this question, Reynaldo created a new square with same dimensions of the former one by translating it 4 centimeters to the left, which means that line segments EF and E'F' have the same length. Let suppose that no further operations have been done.

If $EF = 6\,cm$, then $E'F' = 6\,cm$ because of translation. In other words, the segment $E'F'$ is 6 centimeters long.

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