Question

A Sling Shot accelerates a 12 g Stone to a velocity of
35m/s within a distance of 5.0cm to what (constant force
is the stone subjected during the acceleration

Answer 1

Answer:

Please mark brainliest

Answer 2

Answer:

$\huge\boxed{\sf F = 147 N}$

Explanation:

Given:

Mass = m = 12 g = 0.012 kg

Final Velocity = Vf = 35 m/s

Initial Velocity = Vi = 0 m/s

Distance = S = 5 cm = 0.05 m

Required:

Force = F = ?

Formula:

3rd equation of motion

2aS = Vf²-Vi²

Solution:

2aS = Vf²-Vi²

a = (35)²- (0)² / 2S

a = 1225 / 2(0.05)

a = 1225 / 0.1

a = 12250 m/s²

Force = Mass x Acceleration

F = 0.012 x 12250

F = 147 N

$\rule[225]{225}{2}$

Hope this helped!

~AH1807

Peace!