In △PQR, sinQ=25, sinR=13, and q=6. Find the side length r.
Can someone please help
![In PQR sinQ25 sinR13 and q6 Find the side length r Can someone please help class=](https://us-static.z-dn.net/files/da1/4aaa7da5854af1b3f85b203f317c3280.png)
Answer:
r = 5
Step-by-step explanation:
the sine rules formula :
sin Q/q = sin R/r
=> r = q× sin R / sin Q
= 6× ⅓ / (2/5)
= 2 /(2/5)
= 2× 5/2
= 5
The measure of side length "r" if sinQ=2/5, sinR=1/3, and q=6 is 5
According to the rule, the ratio of the sides to the opposite angles is a constant. Mathematically:
p/sinP = q/sinQ = r/sinR
Given the following parameters
sinQ=2/5, sinR=1/3, and q=6.
6/(2/5) = r/(1/3)
30/2 = 3r
15 = 3r
r = 5
Hence the measure of side length "r" if sinQ=2/5, sinR=1/3, and q=6 is 5
Learn more on sine rule here: https://brainly.com/question/27174058