Respuesta :
Answer:
b = 10
Step-by-step explanation:
Expand the left side and compare the coefficients of like terms
(2x + a)(4x - 1) ← expand using FOIL
= 8x² + 4ax - 2x - a = 8x² + x(4a - 2) - a
Compare coefficients of like terms with
8x² + bx - 3
Then a = 3 ( constant term )
b = 4a - 2 ( coefficients of the x- term )
b = 4(3) - 2 = 12 - 2 = 10
Answer:
b = 10
Step-by-step explanation:
We can break those parenthesis like this
[tex](2x + a)(4x - 1) \\ = 2x(4x - 1) + a(4x - 1) \\ = 8{x}^{2} - 2x + 4ax - a[/tex]
And then combine the terms end with x we get
[tex]8 {x}^{2} - 2x + 4ax - a \\ = 8 {x}^{2} + 4ax - 2x - a \\ = 8 {x}^{2} + (4a - 2)x - a[/tex]
Now by comparing 2 expressions, we can see that a is 3, and b = 4a-2 = 12-2 = 10