Question

(
a. Find the distance around the park to the nearest yard.
39
The distance is about
yards.
b. A new path and a bridge are constructed from point Q to the midpoint M of PR Find QM to the nearest yard.
QM
yd
c. A man jogs from P to Q to M to R to Q and back to P at an average speed of 150 yards per minute. To the neare
long does it take him to travel the entire distance?
It takes about
minutes
Type here to con

Answer 1

We have that the distance around the park to the nearest yard,QM to the nearest yard and the Time of travel for man's jog is given respectively as

• $X=190yd$
• $QM=40yd$
• $T=1.5minutes.$

From the Question we are told that

$PQ=(50-10)=40\\\\QR=(80-10)70$

Generally the equation for the Resultant PR is mathematically given as

$PR=\sqrt{PQ^2+QR^2}\\\\PR=\sqrt{70^2+40^2}\\\\PR=80yd$

a)

Generally the equation for the Distance around they park is mathematically given as

$X=PQ+QR+PR\\\\X=80+70+40$

$X=190yd$

b)

Generally the equation for the Path QM is mathematically given as

From the diagram we see that

$QM=PM=MR\\\\QM=\frac{80}{2}$

$QM=40yd$

c)

From the question we are told

Average speed of $150yd/m$

Total distance traveled

$D_t=40+40+40+70+40\\\\D_t=230yd$

Therefore

Time

$T=\frac{D_t}{V}\\\\T=\frac{230}{150}$

$T=1.5minutes.$

in conclusion

The distance around the park to the nearest yard,QM to the nearest yard and the Time of travel for man's jog is given respectively as

• $X=190yd$
• $QM=40yd$
• $T=1.5minutes.$

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