Question

The ionic radius of a sodium ion is 2.27 angstroms (A) . What is this length in um

Answer 1

$\boxed{\sf 1Å=10^{-10}m}$

$\\ \rm\longmapsto 2.27Å$

$\\ \rm\longmapsto 2.27\times 10^{-10}m$

$\\ \rm\longmapsto 0.227\times 10^{-9}m$

$\\ \rm\longmapsto 0.0227\times 10^{-8}m$

$\\ \rm\longmapsto 0.00227\times 10^{-7}m$

$\\ \rm\longmapsto 0.00023\times 10^{-6}m$

$\\ \rm\longmapsto 0.00023\mu m$

Answer 2

Therefore, length = 2.27 × $10^{-4}$ um

Ionic radius of sodium = 2.27 angstrons

1 angstron = $10^{-10} m$

1 m =$10^6$ micrometer (um)

So, 1 angstron = $10^{-10} m\times10^6 um/m = 10^{-4} um$

Hence,

2.27 anstrons × $10^{-4}$ um/angstron =

2.27 ×$10^{-4}$um

So, length = 2.27 × $10^{-4}$ um

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