Question

1. A car starts from rest and accelerates uniformly for 8.0 s. It reaches a final speed of 15
ms1
a. What is the acceleration of the car?
b. What is the average velocity of the car?
C. Calculate the distance travelled by the car.

Answer 1

Answer:

a. $a=1.875\,ms^{-2}$

b. $v_{0} =7.5\,ms^{-1}$

c. $s=60\,m$

Explanation:

Given,

$u=0\,ms^{-1}\,;[starts\,from\,rest]\\v=15\,ms^{-1}\\t=8\,s$

a. We know,

∴$v=u+at\\=>15=0+a*8\\a=1.875\,ms^{-2}$

b. We know,

∴$s=\frac{u+v}{2}*t\\=>s=\frac{0+15}{2}*8\\s=60\,m$

average velocity,$v_{0} =\frac{s}{t}=\frac{60}{8}=7.5\,ms^{-1}$

c. From b, the answer is 60 m

hope you have understood this....

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