Question

BRAINLIEST : A car starts from rest and accelerates at a rate of 40 m/s2 over a time if 2.4 s. How fast is the car going at the end of this time interval?

Please explain

Answer 1

Answer:

$\boxed {\boxed {\sf 96 \ m/s}}$

Explanation:

We are asked to find the final velocity of the car given the acceleration and time. We can use the following kinematics equation to calculate the final velocity.

$v_f=v_i+(a \times t)$

The car starts from rest, so the initial velocity is 0 meters per second. It accelerates a rate of 40 meters per square second over a period of time of 2.4 seconds.

• $v_i$= 0 m/s
• a= 40 m/s²
• t= 2.4 s

Substitute the values into the formula.

$v_f= 0 \ m/s + ( 40 \ m/s^2 \times2.4 \ s)$

Solve inside the parentheses.

• 40 m/s/s * 2.4 s = 40 m/s * 2.4=96 m/s

$v_f= 0 \ m/s + (96 \ m/s)$

Add.

$v_f= 96 \ m/s$

The final velocity of the car is 96 meters per second.