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Which expression is equivalent?
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Answer: Choice B
[tex]x^{1/8}y^{8}[/tex]
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Explanation:
The two rules we use are
[tex](a*b)^c = a^c*b^c[/tex]
[tex](a^b)^c = a^{b*c}[/tex]
When applying the first rule to the expression your teacher gave you, we can say that:
[tex]\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}[/tex]
Then applying the second rule lets us say
[tex]\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}[/tex]
Therefore,
[tex]\left(x^{1/4}y^{16}\right)^{1/2} = x^{1/8}y^{8}[/tex]
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In short, we just multiplied each exponent inside by the outer exponent 1/2.
So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.