Find three consecutive even numbers
such that the sum of three times the
smaller number and five times the larger
number is 40 more than twice the median
number.

Respuesta :

Answer:

1, 4, 9

Step-by-step explanation:

1 x 3 = 3

9 x 5 = 45

total = 48

median = 4

twice median = 4×2

= 8

sum = 8 + 40 = 48

48=48

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