Question

Find an equation for the line with the given properties. Express the equation in slope-intercept form. Containing the points P = (-4,4) and Q = (-3,2). What is the equation of the line?
y =

Answer 1

Answer:

$y = - 2x - 4$

Step-by-step explanation:

Slope intercept eqn:

$y - y1 = m(x - x1)$

P = (-4,4) and Q = (-3,2)

Let (x1, y1) = (-4,4) and (x2, y2) = (-3,2).

$m = \frac{y2 - y1}{x2 - x1} = \frac{ 2 - 4}{ - 3 - ( - 4)} = \frac{ - 2}{1} = - 2$

Therefore the equation of the line in slope-intercept form :

$y - 4 = - 2(x - ( - 4)) \\ y - 4 = - 2(x + 4) \\ y - 4 = - 2x - 8 \\ y = - 2x - 8 + 4 \\ y = - 2x - 4$