(A) The total distance covered by the plane is 500,000 m
(B) The plane's total displacement is 300,000 m
(C) The average velocity of the plane is 100 m/s
The given parameters:
initial displacement of the plane = 400 km Dallas
final displacement of the train = 100 km Huntsville
the time taken for the initial displacement = 120 min
final time for the second trip = 70 min
A sketch of the plane's trip is as follows:
Dallas
400 km ↑ ↓
↑ ↓ Huntsville 100 km
↑
↑
Houston
(A) The total distance covered by the plane:
The total distance is the total path travelled by the plane.
Total distance = 400 km + 100 km = 500 km, = 500,000 m
(B) The plane's total displacement:
The total displacement is the change in the position of the plane.
The displacement = 400 km - 100 km = 300 km = 300,000 m
(C) The average velocity of the plane
[tex]Average \ velocity = \frac{change \ in \ displacement }{change \ in \ time} \\\\Average \ velocity = \frac{400 \ km - 100 \ km}{120 \ \min - \ 70 \ \min} \\\\Average \ velocity =\frac{300 \ km}{2\ hr - 1.167 \ hr} \\\\Average \ velocity = \frac{300 \ km}{0.833 \ hr} \\\\Average \ velocity = 360.14 \ km/hr\\\\Average \ velocity = \frac{360.14 \ km/h}{3.6 \times \frac{km/hr}{m/s} } = 100 \ m/s[/tex]
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