Question

$(x+3).(x+2)=\sqrt{x^2+4}$

Answer 1

Answer:

OK, so I thought I could solve this but now I'm not so sure. I got $\sqrt{x^{2}+4}$ = $\sqrt{x^{2}+4}$ but this whole thing is such a huge mess I have no idea if it's right or wrong. I tried my best to get it right and I hope this helps.

Step-by-step explanation:

First, let's simplify the left side:

let's make (x + 3) = a and (x + 2) = b

so a · b or ab =

Now let's solve for a:

ab = $\sqrt{x^{2}+4}$

ab/b = ($\sqrt{x^{2}+4}$) / b

a = ($\sqrt{x^{2}+4}$) / b

Now we can substitute a:

[($\sqrt{x^{2}+4}$) / b] · b = $\sqrt{x^{2}+4}$

{[($\sqrt{x^{2}+4}$) / b] · b} / [($\sqrt{x^{2}+4}$) / b] = ($\sqrt{x^{2}+4}$) / [($\sqrt{x^{2}+4}$) / b}

b =  ($\sqrt{x^{2}+4}$) / [($\sqrt{x^{2}+4}$) / b]

Now we can substitute a and b:

[($\sqrt{x^{2}+4}$) / b] · ($\sqrt{x^{2}+4}$) / [($\sqrt{x^{2}+4}$) / b] = $\sqrt{x^{2}+4}$

$\sqrt{x^{2}+4}$ = $\sqrt{x^{2}+4}$