Respuesta :
Answer:
Given coordinetes of triangle A(−2,3),B(8,3) and C(6,7)
AB=
[8−(−2)]
2
+(3−3)
2
=
(10)
2
+(0)
2
=
100
AC=
[6−(−2)]
2
+(7−3)
2
=
(8)
2
+(4)
2
=
64+16
=
80
BC=
(6−8)+[7−(2)]
2
=
(−2)
2
+(4)
2
=
4+16
=
20
If ABC is a right angled triangle, then square of one side must be equal to sum of suare of other two sides.
AB
2
=(
100
)
2
=100
and AC
2
+BC
2
=(
80
)
2
+(
20
)
2
=100
∴AB
2
=AC
2
+BC
2
thus triangle satisfies the Pythagoras theorem
Hence, the triangle is right angled triangle.
Step-by-step explanation:
