Respuesta :

If 10p4₅ = 134₁₀, then p is such that

[tex]10p4_5 = 1\times5^3 + 0\times5^2 + p\times5^1+4\times5^0 \\\\ \implies 134 = 125 + 0 + 5p + 4[/tex]

Solve for p :

134 = 129 + 5p

5 = 5p

p = 1