Question

2. STEM A circuit board manufacturer rejects a 100-ohm resistor if its measured resistance is 0.15 ohm more than or less than 100 ohms. Resistors A and B are rejected. Resistor A's resistance differs from 100 ohms by 0.15 ohm. Resistor B's resistance differs from 100 ohms by -0.78 ohm. How do the resistances of these two resistors compare? Explain.​

Answer 1

The comparison of both resistors is defined by an inequality. Resistor A has a higher resistance than resistor B because $100.15\Omega > 99.22\Omega$

Given that:

$R = 100 \Omega$ ---- the reference resistor

First, we calculate the resistance of both resistors

Resistor A differs by $0.15\Omega$ means that:

$R_A = 100\Omega + 0.15\Omega$

$R_A = 100.15\Omega$

Resistor A has a resistance of $100.15\Omega$

Resistor B differs by $-0.78\Omega$ means that:

$R_B = 100\Omega -0.78\Omega$

$R_B = 99.22\Omega$

Resistor B has a resistance of $99.22\Omega$

By comparing the calculated values, we can conclude that:

Resistor A has a higher resistance than resistor B because $100.15\Omega > 99.22\Omega$

Read more about inequality comparison at:

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