Which is the equation of the line that passes through (6, 2) and is perpendicular to a line with slope -1/3?
![Which is the equation of the line that passes through 6 2 and is perpendicular to a line with slope 13 class=](https://us-static.z-dn.net/files/ddd/a84d3c0c6453ddeae2c70baaf28fa125.jpg)
Answer:
(c) y = 3x - 16 or y - 2 = 3(x - 6)
Step-by-step explanation:
To be perpendicular, the slope must be the negative inverse of the other line,
so we know the slope must be -(-3/1) = 3
then the general point-slope form is
y = mx + b (m = slope and b = y-intercept) so
y = 3x + b (then use the point given (6,2) to find m)
2 = 3(6) + b
2 = 18 + b
2 - 18 = b
-16 = b
then
y = mx + b
y = 3x - 16