Question

can someone please help me answer this function please?

Answer 1

Answer:

B) $x\geq0$

Step-by-step explanation:

The domain of the square root function is all real non-negative numbers. In a numerical format that is as follows:

$D(\sqrt{x})={[0,\infty )}$

This is more commonly denoted as:

$x\geq0$

In the case of the given function:

$g(x)=\sqrt{8x}$

The domain is still ($x\geq0$) as multiplying a value by (8) does not alter this. A negative number times (8) is still negative and thus cannot be a part of the square root domain. Similarly, a positive number times (8) is still positive and remains a part of the square root domain. Moreover, (0) times (8) is still (0).