Question

Find the remainder when f(x) = x^3- 6x^2 +3x -1 divided by 2x-3

Answer 1

Answer:

Remainder is -53/8

Step-by-step explanation:

the divisor is (2x - 3):

make x the subject:

$2x - 3 = 0 \\ 2x = 3 \\ x = \frac{3}{2}$

substitute for x in the function:

$f(x) = {x}^{3} - 6 {x}^{2} + 3x - 1 \\ f( \frac{3}{2} ) = {( \frac{3}{2}) }^{3} - 6 {( \frac{3}{2}) }^{2} + 3( \frac{3}{2} ) - 1 \\ \\ f( \frac{3}{2} ) = \frac{ - 53}{8}$