Question

Amir stands on a balcony and throws a ball to his dog, who is at ground level.
The ball's height (in meters above the ground), xxx seconds after Amir threw it, is modeled by:
h(x)=-(x-2)^2+16h(x)=−(x−2)
2
+16h, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 2, right parenthesis, squared, plus, 16
How many seconds after being thrown will the ball hit the ground?

Answer 1

Answer:

6 seconds

Step-by-step explanation:

h(x)=-(x-2)^2+16

We want h(x) to be 0 ( that is when the ball hits the ground)

0 = -(x-2)^2+16

Subtract 16 from each side

-16  = -(x-2)^2+16-16

-16 = -(x-2)^2

Divide by -1

16 = (x-2)^2

Take the square root of each side

sqrt(16) = sqrt((x-2)^2)

±4 = x-2

Add 2 to each side

2±4 = x-2+2

2±4 =x

2+4 = x   2-4 = x

6 =x  -2 =x

Time cannot be negative so x=6

Answer 2

Answer:

X = 6

Step-by-step explanation:

hope it will help you