Question

Rubidium has an atomic number of 37 and a mass number of 85. How many protons, neutrons, and electrons does an ion of rubidium with a 1+ charge have?(1 point)

A ) 37 protons, 48 neutrons, and 36 electrons

B ) 48 protons, 37 neutrons, and 36 electrons

C ) 37 protons, 48 neutrons, and 38 electrons

D) 48 protons, 37 neutrons, and 38 electrons

Answer 1

the answer would be A :)

Answer 2

An atom has protons, neutrons, and electrons. The protons and neutrons are in the nucleus of the atom, while the electrons are located in the orbital.

An ion of rubidium with a 1+ charge have (option A)

• 37 protons
• 48 neutrons
• 36 electrons

Given that:

$A \to$ Atomic number

$M \to$ Mass number

So:

$A = 37$

$M = 85$

The number of protons is the atomic number (i.e. 37)

The number of neutrons (N) is calculated as follows:

$N = M - A$

$N = 85- 37$

$N = 48$

From the question, we understand that ion is 1+ charge.

This means that we subtract 1 from the atomic number to get the number of electrons (E) i.e.

$E = A -1$

$E =37 -1$

$E =36$

Hence, an ion of rubidium with a 1+ charge have (option A)

• 37 protons
• 48 neutrons
• 36 electrons

Read more about protons, neutrons, and electrons at:

https://brainly.com/question/803445