Give the ratio of sin and tan if cos = 5/13
URGENT!!!
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Answer: anA=sinAcosA=1213513=1213⋅135=125 .
Step-by-step explanation: your welcome hope this helps
Answer:
[tex] \sin( \theta) = \frac{12}{13} [/tex] = 12:13
[tex] \tan( \theta) = \frac{12}{5} [/tex] = 12:5
Step-by-step explanation:
[tex] \cos( \theta) = \frac{adjacent}{hypotenuse} [/tex]
adjacent is 5
hypotenuse is 13
[tex] \sin( \theta) = \frac{opposite}{hypotenuse} [/tex]
but opposite = √(13² - 5²) = 12
[tex] \tan( \theta) = \frac{opposite}{adjacent} [/tex]