Respuesta :
Area=50m^2
Let side be a
[tex]\\ \rm\Rrightarrow Area=a^2[/tex]
[tex]\\ \rm\Rrightarrow a^2=50[/tex]
[tex]\\ \rm\Rrightarrow a=\sqrt{50}[/tex]
[tex]\\ \rm\Rrightarrow a=7.1m[/tex]
Answer:
[tex]\displaystyle 5\sqrt{2}\:m.[/tex]
Step-by-step explanation:
Sinse squares are equal in length all around, this formula applies:
[tex]\displaystyle s^2 = A → \sqrt{50} = \sqrt{s^2} \\ \\ 5\sqrt{2} = s[/tex]
Therefore, the length of the playground is [tex]\displaystyle 5\sqrt{2}[/tex] metres.
* Just in case you could not figure out how to find the square root of fifty, here is how using perfect squares:
[tex]\displaystyle \sqrt{50} → \sqrt{2 \times 25} \\ \\ 5\sqrt{2}[/tex]
Sinse we are dealing with measurements, we only want the NON-NEGATIVE root.
I am joyous to assist you at any time.