Question

Supposed a certain game is fair and costs $4 if you lose and has a net payoff of $9 if you win. The only
possible outcomes of the game are winning and losing.
What is the probability of winning?

Answer 1

Answer:

32.5% Win Rate

Step-by-step explanation:

I got this answer by first:

( 9 ) * x + ( -4 ) * ( 1 - x ) = 0

9x - 4 + 4x = 0

13x = 4

then finally:

13/4 = 3.25 | And to get that into percent you multiply that by 10, giving you a 32.5% win rate. or 325 / 1000. Meaning you will win 325 out of 1000 games you play. Hope this helped!

Answer 2

Probability of winning is 0.69.

What is probability?

Probability denotes the possibility of the outcome of any random event. The meaning of this term is to check the extent to which any event is likely to happen.

According to the question

Supposed a certain game is fair and costs $4 if you lose and has a net payoff of $9 if you win.

The only possible outcomes of the game are winning and losing.

The probability of winning = $\frac{9}{4+9}$

= $\frac{9}{13}$

= 0.69

Hence, probability of winning is 0.69.

Find out more information about probability here

https://brainly.com/question/11234923

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