Question

The moon Phobos orbits Mars
(m = 6.42 x 10^23 kg) at a distance of
9.38 x 10^6 m. What is the Phobos'
orbital velocity?
[?] m/s

Answer 1

Explanation:

For a circular orbit v= $\sqrt{\frac{G.m}{r} }$ with G = 6.6742 × $10^{-11}$

Given m = 6.42 x 10^23 kg and  r=9.38 x 10^6 m

=> v = 2137.3 m/s

I hope this is the correct way to solve