Hi there!
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I believe your answer is:
[tex]6525\text{cm.}^3[/tex]
Keep in mind that this is APPROXIMATE.
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Here’s why:
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[tex]\boxed{\text{Volume of a Sphere Is:}}\\\\V = \frac{4}{3} \pi r^3\\----------------\\\rightarrow \text{We are given the radius of } 11.6\text{ cm.}\\----------------\\V = \frac{4}{3}(3.14) (11.6)^3\\\\V = \frac{4}{3}(3.14) 1560.896\\\\V \approx 6534.95125\text{cm.}^3\\\\\boxed{V \approx 6535\text{cm.}^3}[/tex]
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Hope this helps you. I apologize if it’s incorrect.