Question

$-4\sqrt{28x}$ times $\sqrt{7x^3}$

Answer 1

Answer:

${56x}^{2}$

Step-by-step explanation:

$- 4 \sqrt{28x} \times \sqrt{ {7x}^{3} }$

$= -4 \times 2 \sqrt{7x} \times \sqrt{7x}$

$= - 4 \times 2 \times 7x \times x$

$= {56x}^{2}$