Question

Three resistors 2 k\ohm, 2.5 k\ohm and 3 k\ohm are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA).

Answer 1

Answer:

1.33 mA

Explanation:

V=IR

I=10/(7.5×10³)

=1.33×10-³A

=1.33mA