Question

URGENT WILL MARK BRAINLIEST
Show your work and solve for x and y.
3x + y = 8
2x + 4y = 12

Answer 1

Answer:

x=2, y=2

Step-by-step explanation:

3x + y = 8

2x + 4y = 12

Multiply the first equation by -4

-12x -4y = -32

Then add to the second equation

-12x -4y = -32

2x + 4y = 12

------------------------

-10x + 0y = -20

-10x = -20

Divide by -10

-10x/-10 = -20/-10

x =2

Now find y

3x+y = 8

3(2)+y = 8

6+y = 8

y = 8-6

y =2

Answer 2

Answer:

$\huge\boxed{\sf Solution Set = \{(2,2)\}}$

Step-by-step explanation:

3x + y = 8 ----------------------(1)

2x + 4y = 12 -------------------(2)

Multiply Eq. (1) by 4

4(3x+y) = 8*4

12x + 4y = 32 -----------------(3)

Subtract Eq. (3) from (2)

2x + 4y - (12x + 4y) = 12 - 32

2x + 4y - 12x - 4y = -20

2x - 12x = -20

-10x = -20

Divide both sides by -10

x = 2

Put x = 2 in Eq. (1)

3(2) + y = 8

6 + y = 8

Subtract 6 to both sides

y = 8 - 6

y = 2

Solution Set = {(x,y)} = {(2,2)}

$\rule[225]{225}{2}$

Hope this helped!

~AH1807

Peace!