Question

The sum of 5 consecutive integers is 110 what is the 4th number of this sequence

Answer 1

Step-by-step explanation:

Let 5 consecutive no. be

n, n+1,n+2,n+3,n+4

n+n+1+n+2+n+3+n+4=110

5n+10=110

5n=110-10

5n=100

n=100/5

n=20

4th term is n+3=20+3=23

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