Question

Which is 6 logx + 5log(x - 8) written as a single logarithm?

Answer 1

Answer:

log ($x^{6}$$(x-8)^{5}$

Step-by-step explanation:

Using the rules of logarithms

log $x^{n}$ ⇔ nlog x

log x + log y = log(xy)

Given

6 log x + 5log(x - 8)

= log$x^{6}$ + log$(x-8)^{5}$

= log ($x^{6}$$(x-8)^{5}$ )

Answer 2

Answer:

d) on edge

Step-by-step explanation:

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