Question

if the 6th term of an A.p is 11and its first term is 1 find the common diferent​

Answer 1

Answer:

2

Step-by-step explanation:

In an AP, Tn = a + (n - 1)d

T6 = a + 5d = 11

The first term = a = 1

∴ T6 = 1 + 5d = 11

5d = 11 - 1

5d = 10

∴ d = 2

I hope this will help you :-)

Answer 2

Answer:

$x6 = 11 \\ x1 = 1 \\ x6 \: can \: be \: written \: as \: x6 = x1 + 5d \\ x6 = 1 + 5d \\ 11 = 1 + 5d \\ 10 = 5d \\ d = \frac{10}{5} \\ d = 2 \\ thank \: you$