Question

1. Point B bisects AC. If AB = 2x + 10, and AC = 40, what is the value of x

Answer 1

Answer:

x = 5

Step-by-step explanation:

B, bisects AB. So, AB = BC

AC = AB  +BC

     = AB + AB

AC = 2AB

$\dfrac{1}{2}AC = AB\\\\AB = \dfrac{1}{2}AC\\\\2x + 10 =\dfrac{1}{2}*40\\\\2x + 10 = 20$

Subtract 10 from both sides,

2x = 20 - 10

2x = 10

Divide both sides by 2

x = 10/2

x = 5