Question

An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car that is moving at a constant velocity of 30m/s. How far must the ambulance travel until it matches the car’s velocity?

Answer 1

• initial velocity=15m/s=u
• Acceleration=a=5m/s^2
• Final velocity=v=30m/s
• Distance be s

Using 3rd equation of kinematics

$\\ \rm\longmapsto v^2-u^2=2as$

$\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}$

$\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}$

$\\ \rm\longmapsto s=\dfrac{900-225}{10}$

$\\ \rm\longmapsto s=\dfrac{675}{10}$

$\\ \rm\longmapsto s=67.5m$