Question

2. A force of 20N acts on a particle of mass 2 Kg and displaces it by 5m at an angle 30°. What is the work done? a) 40J ) b) 50 J c) 100J​

Answer 1

Mass is not required

• Force=F=20N
• Angle=30°
• Displacement=s=5m

$\\ \rm\longmapsto W=Fscos\Theta$

$\\ \rm\longmapsto W=20(5)cos30$

$\\ \rm\longmapsto W=100\times \dfrac{\sqrt{3}}{2}$

$\\ \rm\longmapsto W=50\sqrt{3}J$

Answer 2

Answer:

$we \: have \\ w = fs \cos( \alpha ) \\ f = 20n \\ m = 2kg \\ s = 5m \\ \alpha = 30 \\ \\ then \: w = 20 \times 5 \times \cos(30) \\ 100 \cos(30) \\ = 100 \frac{ \sqrt{3} }{2} \\ = 50 \sqrt{3} \\ = 86.6 \: joule\\ thank \: yo$