The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.
What is the length between two points in a plane?
The length between two given points (x₁, y₁) and (x₂, y₂) will be:
√[(x₂ - x₁)² + (y₂ - y₁)²] units
Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).
Therefore, the diagonals of the quadrilateral will be AC and BD.
The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).
Now, the length of the diagonal AC will be:
= √[(-8 - 4)² + (2 - (- 3))²] units
= √[(- 12)² + (5)²] units
= √[144 + 25] units
= √(169) units
= 13 units (length can't be negative)
Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).
Now, the length of the diagonal BD will be:
= √[(-1 - 7)² + (- 5 - 10)²] units
= √[(- 8)² + (- 15)²] units
= √[64 + 225] units
= √(289) units
= 17 units (length can't be negative)
Learn more about the length between two points on a plane here: https://brainly.com/question/14898312
#SPJ2
