Answer:
Experiment
Materials needed
Stop watch, a small stone, a big stone, a balance.
Procedure
Measure the mass of the two stones.
Hold the two stones about 5m above the ground level.
Drop the stones simultaneously.
Record the time taken for the stones to strike the ground.
Repeat the procedure with different masses of objects at the same height.
Observation, it will be observed that, all the objects dropped from the same height strike the ground at the same time interval.
Conclusion; a falling object doesn't depend on mass
Explanation:
½mv²=mgh
g=½(V²/h)
When an object is held at a height, it posses gravitational potential energy which is mgh, where m= mass, h=height, g=acceleration due gravity
When the object is dropped, the potential energy will be converted to kinetic energy which is ½mv², where V=velocity at which the object moves.
V=∆h/t, ∆h is change in height with respect to time.
½mv²=mgh
Mass cancel out,
g=v²/2h
This implies that g does not depend or is not affected by mass. Hence heavy object and light object will reach the ground at the same time when dropped from the same height. When air resistance is negligible.
