Question

PLease help and explain

Answer 1

• 4x+3y=23----(1)
• x-5y=0----(2)

From eq(2)

$\\ \sf\longmapsto x-5y=0$

$\\ \sf\longmapsto x=5y\dots(3)$

• Put the value in eq(1)

$\\ \sf\longmapsto 4x+3y=23$

$\\ \sf\longmapsto 4(5y)+3y=23$

$\\ \sf\longmapsto 20y+3y=23$

$\\ \sf\longmapsto 23y=23$

$\\ \sf\longmapsto y=1$

• Put the value in eq(3)

$\\ \sf\longmapsto x=5y$

$\\ \sf\longmapsto x=5(1)$

$\\ \sf\longmapsto x=5$

Hence

(x,y)=(5,1)