Question

A chocolate factory has three classifications for the candies that it makes:
Caramels (12 varieties). please help!!!
Milk Chocolate (6 varieties)
Dark Chocolate (9 varieties)
1. Set up the NOTATION to figure out the different ways to choose 7 of the 12 Caramels
2. Set up the NOTATION to figure out the different ways to choose 3 of the 6 Milk Chocolates
3. Set up the NOTATION to figure out the different ways to choose 5 of the 9 Dark Chocolates
4. A customer has ordered an assortment to consist of seven types of caramels, three types of chocolate, and five types of dark chocolates.
How many such assortments are possible?

Answer 1

Answer:

1. 792 2. 20. 3. 126. 4.1995840

Step-by-step explanation:

Use the formula C(n,r)= n!/ r/ (n-r)! where n is total quantity of varieties and r is the quantity uou should choose.

1) n=12 (total quantity); r= 7

C(12,7)= 12!/(7! *(12-7)!)= 8*9*10*11*12/ (5*4*3*2)= 8*9*11= 72*11= 792

2) n=6 r=3

C(6,3)= 6!/ (3! * (6-3)!)= 6!/ (3!)^2= 4*5*6/ 3*2= 20.

3) C(9,5)= 9!/ (5!*4!)= 6*7*8*9/ (4*3*2*1)= 2*63= 126

4) You need to choose the whole set which consists of three components that has been defined. Multiply previous results

792*20*126= 1995840.