Question

Please help its urgent:

A bag contains one tile for each letter of the word PANDA. If you selected a permutation of these letters at random, what is the probability that they would spell the word panda?

Answer 1

Answer:

• 1/60

Step-by-step explanation:

Permutations of "Panda"

• 5P5 = 5! = 120

Two of the 'Panda" s we can get as a result

• P(Panda) = 2/120 = 1/60

Answer 2

Using Permutation

$\boxed{\sf ^nP_r=n!}$

$\\ \sf\longmapsto ^5P_r=5!$

$\\ \sf\longmapsto 1\times 2\times 3\times 4\times 5$

$\\ \sf\longmapsto 120$

Now

$\\ \sf\longmapsto P(Panda)=\dfrac{2}{120}$

$\\ \sf\longmapsto P(Panda)=\dfrac{1}{60}$