Question

$10 bet between you and me. At any time during the game, I can ask to double it. If you accept we both put in another $10 and if you win, you win the $20 and if you lose, you lose it all. If you reject, you lose the initial $10. What is the minimum probability you would take to accept the double

Answer 1

Answer:

66%

Step-by-step explanation:

$-10x\:+\:\left(20\cdot \left(1-x\right)\right)=\:0$

x = $\frac{2}{3}$ = .666 = 66%